/*
   ACM North Central Region, 1993-94
   Problem D, Evaluating Simple C Expressions

   Ed Karrels, April 1996
*/

#include <stdio.h>
#include <ctype.h>

int Token (char s[], int *i) {
   while (isspace(s[*i])) ++*i;
   if (!s[*i]) return 0;
   if (s[*i] == '+') {
      if (s[*i+1] == '+') {
	 *i += 2;
	 return '*';
      } else {
	 ++*i;
	 return '+';
      }
   }
   
   if (s[*i] == '-') {
      if (s[*i+1] == '-') {
	 *i += 2;
	 return '/';
      } else {
	 ++*i;
	 return '-';
      }
   }
   
   return s[(*i)++];
}

#define NT nt = Token(L, &p)

int main() {
   int v[26], i, p, pre, post[26], f=1, sum, vn, used[26];
   char L[100], nt;

   fgets(L, 100, stdin);
   L[strlen(L)-1] = 0;
   while (strlen(L)) {
      printf("Expression: %s\n", L);
      for (i=0; i<26; i++) {
	 v[i] = i+1;
	 used[i] = 0;
	 post[i] = 0;
      }
      f = 1;
      p = sum = 0;
      NT;
      while (1) {
	 pre = 0;
	 if (nt=='*') {pre++; NT;}
	 if (nt=='/') {pre--; NT;}
	 if (!isalpha(nt)) {printf("no var name\n"); exit(1);}
	 vn = nt - 'a'; v[vn] += pre; used[vn] = 1;
	 sum += f*v[vn];
	 NT;
	 if (nt == '*') {post[vn]++; NT;}
	 if (nt == '/') {post[vn]--; NT;}
	 if (nt==0) break;
	 f = (nt=='+') ? 1 : -1;
	 NT;
      }
      printf("    value = %d\n", sum);
      for (i=0; i<26; i++) 
	 if (used[i])
	    printf("    %c = %d\n", 'a'+i, v[i]+post[i]);
      fgets(L, 100, stdin);
      L[strlen(L)-1] = 0;
   }

   return 0;
}