/*
   ACM North Central Region, 1994-95
   Problem G, Interpreting Control Sequences

   Ed Karrels, May 1996
*/

#include <stdio.h>

void Put(char sc[10][10], int *x, int *y, int ovr, char c) {
   int i;
   if (!ovr) {
      for (i=8; i >= *x; i--) sc[i + 1][*y] = sc[i][*y];
   }
   sc[*x][*y] = c;
   if (*x < 9) ++*x;
}


int main() {
   char sc[10][10];
   int x, y, l, nl, ovr=1, i, j, cs=1;
   char c;

   while (scanf("%d ", &nl), nl) {

      for (i=0; i<10; i++)
	 for (j=0; j<10; j++)
	    sc[i][j] = ' ';

      x = y = 0;
      while (nl) {
	 c = getchar();
	 if (c == '^') {
	    c = getchar();
	    switch (c) {
	     case 'b':
	       x = 0;
	       break;
	     case 'c':
	       for (i=0; i<10; i++)
		  for (j=0; j<10; j++)
		     sc[i][j] = ' ';
	       break;
	     case 'd':
	       if (y<9) y++;
	       break;
	     case 'e':
	       for (i=x; i<10; i++) sc[i][y] = ' ';
	       break;
	     case 'h':
	       x = y = 0;
	       break;
	     case 'i':
	       ovr = 0;
	       break;
	     case 'l':
	       if (x>0) x--;
	       break;
	     case 'o':
	       ovr = 1;
	       break;
	     case 'r':
	       if (x<9) x++;
	       break;
	     case 'u':
	       if (y>0) y--;
	       break;
	     case '^':
	       Put(sc, &x, &y, ovr, '^');
	       break;
	    }
	    if (isdigit(c)) {
	       y = c - '0';
	       x = getchar() - '0';
	    }
	 } else if (c != '\n') {
	    Put(sc, &x, &y, ovr, c);
	 } else {
	    nl--;
	 }
      }  /* while */
      
      printf("Case %d\n", cs++);
      printf("+----------+\n");
      for (i=0; i<10; i++) {
	 putchar('|');
	 for (j=0; j<10; j++) {
	    putchar(sc[j][i]);
	 }
	 putchar('|');
	 putchar('\n');
      }
      printf("+----------+\n");
	 
   }

   return 0;
}